Generate Parentheses - Go Solution
Solving the LeetCode "Generate Parentheses" Problem in Go
Introduction
Generating all combinations of well-formed parentheses is a classic problem that tests understanding of recursion and backtracking. It is commonly encountered in technical interviews and competitive programming.
Problem Analysis
Given an integer n
, the task is to generate all possible valid combinations of n
pairs of parentheses. A combination is valid if every opening parenthesis has a corresponding closing parenthesis. For example, when n = 3
, the valid combinations are ["((()))","(()())","(())()","()(())","()()()"].
Solution Approach
The problem can be efficiently solved using backtracking. The idea is to build the combinations incrementally, ensuring at each step that the number of opening parentheses is never less than the number of closing parentheses. We recursively explore all valid paths by adding either an opening or closing parenthesis when the constraints allow it.
Go Implementation
func generateParenthesis(n int) []string {
var result []string
backtrack(&result, "", 0, 0, n)
return result
}
func backtrack(result *[]string, current string, open, close, max int) {
if len(current) == max*2 {
*result = append(*result, current)
return
}
if open < max {
backtrack(result, current+"(", open+1, close, max)
}
if close < open {
backtrack(result, current+")", open, close+1, max)
}
}
Complexity Analysis
The time complexity is O(4^n / sqrt(n)), as each valid sequence has at most n
steps, and the number of valid sequences is the nth Catalan number. The space complexity is O(n) due to the recursion stack, not accounting for the space required to store the result.
Testing and Examples
Test cases include:
n = 1
: Output should be ["()"]n = 2
: Output should be ["(())","()()"]n = 3
: Output should be ["((()))","(()())","(())()","()(())","()()()"]
Best Practices and Tips
Key takeaways include understanding the constraints of valid parentheses, leveraging backtracking to explore all possibilities, and optimizing the solution by pruning invalid paths early. Always validate your solution with edge cases like n = 1
and n = 8
.